(3x^2+2x)^2+8=27x^2+18x

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Solution for (3x^2+2x)^2+8=27x^2+18x equation: 



(3x^2+2x)^2+8=27x^2+18x

We move all terms to the left:

(3x^2+2x)^2+8-(27x^2+18x)=0

We get rid of parentheses

-27x^2+(3x^2+2x)^2-18x+8=0

We add all the numbers together, and all the variables

-27x^2-18x+(3x^2+2x)^2+8=0

We move all terms containing x to the left, all other terms to the right

-27x^2-18x+(3x^2+2x)^2=-8

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